1)1+3=4(гон) Стоят 2 конфеты
2)4:2=2(Гон)-1конфета
X+1\9*(x-(3\5)*x-21\40))=(x-4)\6
x+(1\9)*x-(3x\45)-21\360=(x-4)\6
(10\9)*x-3x\45-21\360=(x-4)\6
60x\9-18x\45-126\360=x-4
300x\45-18x\45-126\360=x-4
2400x\360-144x\360-126\360=x-4
(2256x-126)\360=x-4
2256x-126=360x-1440
2256x-360x=126-1440
1896x=1314
x=1314\1896=657\948
<span>(7a+a):13=416,
8а:13=416,
8а=416*13,
8а=5408,
а=5408:8,
а=676.
Ответ: 676.</span>
По теореме Виета
![x1 + x2 = - b \ \div a \\ x1 \times x2 = c \div a \\](https://tex.z-dn.net/?f=+x1++%2B+x2+%3D++-+b+%5C+%5Cdiv++a+%5C%5C+x1++%5Ctimes+x2+%3D+c+%5Cdiv+a+%5C%5C+)
4 3/4= 4.75
-0.25+4.75=-b/16
4.5*16=-b
b=-72
(-0.25)*(4.75)=c/16
c=16*(-1/4)*4.75=(-4)*19/4=-19