CH4+CL=HCL+CH3CL
2CH3CL+2Na=C2H6+2NaCL
C2H6+Br2=C2H5Br+HBr
2Al+3Г2=2AlГ3
2 3
m(Г2)=80,1-8,1=72;n(Al)=8,1:27=0,3;n(Г2)=0,3*1,5=0,45;M(Г2)=72:0,45=160г/моль
Ответ:J2
С + O2 = CO2
n(CO2) = 336/22.4 = 15 моль
n(C) = n(CO2)=15 моль
M(C)=12 г/моль
m(C) = 15 *12 = 180 г
w(C) = 180/187.52 *100% = 96%