Question

Найдите решение системы уравнений способом подстановки:5х-2(у+4)=0 внизу 6(2х+3)-у=41

Answer 1

 $\left \{ {{5x-2(y+4)=0} \atop {6(2x+3)-y=41}} \right. \left \{ {{5x-2y-8=0} \atop {12x+18-y=41}} \right. \left \{ {{5x-2y-8=0} \atop {y=12x-23}} \right. \left \{ {{5x-2(12x-23)-8=0} \atop {y=12x-23}} \right. \left \{ {{19x=38} \atop {y=12x-23}} \right.$

$\left \{ {{x=2} \atop {y=12*2-23=1}} \right.$