Question

Найдите значение выражения x^2-25 \ x^3 - 10x^2 + 25x * x-5 \ 2x при x= - 0,2

Answer 1

1) (2(3+x)- 4x - (3-x))/(3-x)(3+x)*(3+x)^2=(6 +2x- 4x - 3 - x)/ (3-x) * (3+x)=(3-3x)/(3-x) * (3+x)2) ~~~ =(x^2-25)+50*(x-5)/(x^2+25)=(x^2-25+50)(x-5)/(x^2+25)=(x^3-5x^2-25x+125+50x-250)/(x^2+25)=(x^3-5x^2+25x-125)/(x^2+25)3) (х - (x/1-x) : 3x*4/(x^2-2x+1) = (1/6 - (1/6: 5/6) : 1/2*4/(1/6 - 1)^2 =(1/6 -1/5) : 2/(-5/6)^2= -1/30 : 2:25/36 =25/36:60 = 25/36*60 =5/36*12=5/432