Question

Log12 432 + log12 48

Answer 1

$log_{12}432+ log_{12} 48= log_{12}(432*48)= log_{12} (144*3*12*4) =$
=$= log_{12} ( 12^{2}*12*12 )= log_{12} 12^{4}=4$

Answer 2

Log(12) 432 + Log(12) 48 = Log(12) 432*48 = Log(12) 20736=4