X( 2x^2 - 5x - 3) = 0
x=0
2x^2 - 5x - 3 = 0
D = b^2 - 4ac = 25 + 24 = 49 = 7^2
x1 = ( 5 + 7) / 4 = 3
x2 = ( 5 - 7) / 4 = - 0,5
Ответ: x1 = 3, x2 = - 0,5, x3 = 0
27vt^3+343t^3=t^3(27v+343)
Х(6х+1)дробь
в знаменателе уравнение
6х²-17х-3=0
D=289-4*6*(-3)=361
x=17+19/12=3
x=17-19/12= -1/6
х(6х+1)дробь 6(x+1/6)(x-3)=
=х(6х+1)дробь (6х+1)(х-3)=
х дробь х-3