N(h2o)=1.6/16=0.1 моль
m(nacl)=0.1 * 58.5= 5.85 г
<span><span>4Fe</span>+<span>3<span>O2 </span></span>→ <span>2<span>Fe2O3
</span></span></span><span><span>Fe2O3</span>+<span>6<span>HCl</span></span> → <span>2<span>FeCl3</span></span>+<span>3<span>H2O </span></span></span>
<span><span>FeCl3</span>+<span>3<span>NaOH</span></span> → <span>3<span>NaCl</span></span>+<span>Fe<span>(OH)</span>3
</span></span><span><span>2<span>Fe<span>(OH)</span>3</span></span>+<span>3<span>H2SO4</span></span> → <span>Fe2<span>(SO4)</span>3</span>+<span>6<span>H2<span>O
</span></span></span></span>
Аргон тртртртрглппнапщамгне