2Met+I2=2MetI
n(Met)=9,2/Mr моль
n(MetI)=60/(Mr+127×2) моль
Прировняем и составим уравнение:
60/(Mr+127×1)= 9,2/Mr
9,2 (Mr+127)=60Mr
9,2Mr+1168,4=60Mr
50,8Mr=1168,4
Mr=23
Искомый металл: Na
1-4
2-2
3-4 .........................................................
<span>Si</span>⁺⁴<span>O</span>²⁻<span>2.Si</span>⁺⁴<span>Cl</span>⁻<span>4.Mg</span>²⁺<span>2Si</span>⁴⁻<span>.H</span>⁺<span>2S</span>⁺⁴<span>O</span>²⁻<span>3.K</span>⁺<span>N</span>⁺⁵<span>O</span>²⁻<span>3.K</span>⁺<span>2Cr</span>⁺⁶<span>2O</span>²⁻<span>7</span>