NH4Cl+NaOH→X→NO<span>→N2O
</span>1) NH4Cl+NaOH=NaCl+NH3<span>↑ +H2O
2) 4NH3+5O2=4NO+6H2O
3) 2NO+H2=N2O+H2O
X - NH3 - аммиак.</span>
AlBr3 + Na3PO4 -> AlPO4 + 3NaBr
AlBr3 + 3AgNO3 -> Al(NO3)3 + 3AgBr
AlBr3 + H3PO4 -> AlPO4 + 3HBr
AlBr3 + 3LiOH -> Al(OH)3 + 3LiBr
2AlBr3 + 3Pb(NO3)2 -> 2Al(NO3)3 + 3PbBr2
Fe + 2 HCl = FeCl2 + H2
M(Fe) = 56 г/моль
m(Fe) = 210 - 210*0.04 =201.6
n(Fe) = 201.6/56 = 3.6 моль
n(H2) = n(Fe) = 3.6 моль
V(H2) = 3.6 * 22.4 = 80.64 л