1) cos(x/2-π/12)=0
x/2-π/12=π/2 + πk, k∈Z
x/2=π/12 + π/2 + πk
x/2= π/12 + 6π/12 + πk
x/2 = 7π/12 + πk
x= 2(7π/12 + πk)
x=7π/6 + 2πk, k∈Z
2) sin(x-π/3)+1=0
sin(x-π/3)= -1
x-π/3= -π/2 + 2πn, n∈Z
x=π/3 - π/2 + 2πn
x=2π/6 - 3π/6 + 2πn
x= - π/6 + 2πn, n∈Z
Ответ: 7π/6 + 2πk, k∈Z;
- π/6 + 2πn, n∈Z
<u>1.</u> если график функции x+by=3 проходит через точку (1;-1),
то значение коэффициента b:
1-b=3; b=-2
<u><em>Ответ: -2</em></u>
<u>2.</u>
![\frac{9}{x-3}+2=5\\ x\neq 3\\9+2x-6=5x-15\\3x=18\\x=6](https://tex.z-dn.net/?f=%5Cfrac%7B9%7D%7Bx-3%7D%2B2%3D5%5C%5C%20x%5Cneq%203%5C%5C9%2B2x-6%3D5x-15%5C%5C3x%3D18%5C%5Cx%3D6)
<u><em>Ответ: 6</em></u>