Question

Разложи на множители 0,001−0,1y−y^2+y^3

Answer 1

$0.001-0.1y-y^2+y^3=y^3+0.001-y^2-0.1y=$
$=(y)^3+(0.1)^3-y(y+0.1)=$
$=(y+0.1)(y^2-0.1y+0.1^2)-y(y+0.1)=$
$=(y+0.1)(y^2-0.1y+0.1^2-y)=(y+0.1)(y^2-1.1y+0.01)$