<span>Log_2 (3)- log_2 (24) = log_2(x)
</span>Log_2 (3/24)=Log_2 (х)
Log_2 (1/8)=Log_2 (х)
х=1/8 =2⁻³
-56m^2+16mu+35am-10au=-16m(3,5m-u)+10a(3,5m-u)=(10a-16m)(3,5m-u)
Здравствуйте!
Сначала нужно привести дробную часть к общему знаменателю:
Теперь сложим дроби:
ОТВЕТ: 20 11/24
Cos(2x/3+π/4)=1/√2
2x/3+π/4=+-arcos(1/√2)+2πn, n∈Z
2x+π/4=π/4+2πn, n∈Z или 2x+π/4=-π/4+2πn, n∈Z
2x=2πn, n∈Z 2x==-2π/4+2πn, n∈Z
x=πn, n∈Z x=-π/2+πn, n∈Z
ответ: х1=πn, n∈Z, x2=-π/2+πn, n∈Z
<span>2<span>a^3</span>+<span>a^2</span>−1−3<span>a^2</span>+<span>a^3</span>−a=</span><span>3<span>a^3</span>−2<span>a^2</span>−1−a=</span><span><span>3<span>a^3</span>−2<span>a^2</span>−a−1</span></span>