2Al+3S=Al2S3
2CH4=C2H2+3H2
2Fe+3Cl2=2FeCl3
2Cu+O2=2CuO
А второе задание не видно
Ответ:
дано
m( ppa Ba(NO3)2) = 2.61 g
W(Ba(NO3)2) = 10%
----------------------------
m(BaSO4) - ?
m(Ba(NO3)2) = 2.61 * 10% / 100% = 0.261 g
M(Ba(NO3)2) = 261 g/mol
n(Ba(NO3)2) = m/M = 0.261 / 261 = 0.001 mol
K2SO4+Ba(NO3)2 = 2KNO3+BaSO4↓
n(Ba(NO3)2) = n( BaSO4) = 0.001 mol
M( BaSO4) = 233 g/mol
m(BaSO4) = n*M = 0.001 * 233 = 0.233 g
ответ 0.233 г
Объяснение:
8,8г хг
С3Н8 + 5О2 = 3СО2 + 4Н2О
44г 3х44г
V (C3H8<span>) = 26,4 ∙ 22,4 / 44 = 13,44 (л).</span>
3Cu
+ 8HNO₃<span> (разб)→ 3Cu(NO</span>₃)₂<span> + 2NO↑ + 4H</span>₂<span>O
Сu</span>₂O + 2HNO₃ = 2CuNO₃ + H₂O
NaOH + HNO₃ = NaNO₃ + H₂O
<span>5Ca + 12HNO₃→ 5Ca(NO₃)₂ + N₂ + 6H₂<span>O
KCl + HNO</span></span>₃≠
CO₂ + HNO₃≠