N( H2SO4) = m(H2SO4) / M(H2SO4) =196/98 = 2моль
N2 + 3H2 = 2NH<span>3
</span>2NH3 +<span> H</span>2SO4 =<span> (NH</span>4)2SO<span>4
</span>(NH4)2SO4 +<span> BaCl</span>2 = 2NH4<span>Cl </span>+<span> BaSO</span><span>4
</span>NH4<span>Cl </span>+<span> NaOH </span>=<span> NaCl </span>+<span> NH</span>3 +<span> H</span>2<span>O
</span>NH3 +<span> HNO</span>3 =<span> NH</span>4NO<span>3</span>
H2 + S = H2S - сероводород
2H3PO4 + 3Mg = Mg3(PO4)2 + 3H2
Возможно так: C6H11IO6+HI