Структурные формулы в фото ниже......................
Вот твой ответ 1.10000000E+24
Mr(Ba(OH)2) = 137+2*16+2*1 = 171
W(Ba) = 137/171 = 0.80=80%
W(O) = 32/171 = 0.19=19%
W(H)=2/171=0.01=1%
Mr(Al(SO4)3) = 27+3*32+12*16 = 315
W(Al) = 27/315 = 0.09=9%
W(S) = 96/315=0.30=30%
W(O)= 192/315 = 0.61=61%
Mg + 2HCl = MgCl2 + H2
n(Mg) = n(H2)
V(H2) = 3*22,4 = 67,2 литра
n(Mg) = n(MgCl2)
m(MgCl2) = 3*95 = 285 гр.
10Al + 6KNO3 = 6KAlO2 + 2Al2O3 + 3N2