Question

Найдите корень уравнения: 2$2^x^2^-^8^x^+^1^9$

Answer 1

2^(x²-8x+19)=16
2^(x²-8x+19)=2^4
x²-8x+19=4
x²-8x+19-4=0
D/4=16-15=1=+-1²
x1=4-1=3
x2=4+1=5

Answer 2

X^2 - 8x + 19 = 4
x^2 - 8x + 15 = 0
D = 16 - 15 = 1
x = 4+-1 = 5; 3