1. СН3-СН2-СН2-СН2-СН2-СН2-СН2-СН3
2. СН3-СН2-СН2-СН2-СН2-СН-СН3
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СН3
3. СН3-СН2-СН2-СН2-СН-СН2-СН3
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СН3
4. СН3-СН2-СН2-СН-СН2-СН2-СН3
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СН3
5. СН3-СН2-СН2-СН-СН-СН3
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СН3 СН3
6. СН3-СН2-СН-СН2-СН-СН3
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CH3 CH3
7. CH3-CH-CH2-CH2-CH-CH3
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CH3 CH3
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CH3
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8. CH3-CH2-CH2-CH2 - C- CH3
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CH3
9. CH3-CH2-CH-CH-CH2-CH3
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CH3 CH3
CH3
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10. CH3-CH2-CH2 - C - CH2-CH3
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CH3
11. CH3-CH2-CH2-CH-CH2-CH3
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CH2
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CH3
12. CH3-CH-CH-CH-CH3
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CH3 CH3 CH3
13.CH3-CH2-CH-CH-CH3
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CH2 CH3
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CH3
CH3
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14. CH3-CH2-CH- C - CH3
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CH3 CH3
Вот,держи. Увеличение электрохимических потенциалов
1) 2Na+ Cl2 = 2NaCl
2) NaCl+H2SO4=NaHSO4+HCl
3) <span>Ca + 2HCl = CaCl2 + H2↑
</span>4) <span>CaCl2 + 2AgNO3 = 2AgCl + Ca(NO3)2</span>
2CH₃-CH₂-CH₂-CH₂-CH₂OH + 2Na = 2CH₃-CH₂-CH₂-CH₂-CH₂ONa + H₂↑
m(C₅H₁₁OH)чист.=(W%(C₅H₁₁OH)*m(C₅H₁₁<span>OH))/100%=(96*1000)/100=960г
n(</span>C₅H₁₁OH)=m(C₅H₁₁OH)/M(C₅H₁₁<span>OH) = 960/88 = 10,9 моль
по уравнению реакции - n(H</span>₂)= n(C₅H₁₁<span>OH)/2 = 10,9/2 = 5,45 моль
V(H</span>₂) = n(H₂)*Vm = 5,45*22,4 = 122,08 л
ответ: V(H₂) = 122.08 л