Question

Сократите дробь: 10а²-6а+5аб-3б _____________ 5а²-8а+3

Answer 1

$\frac{10a^2-6a+5ab-3b}{5a^2-8a+3} = \frac{5a(2a+b)-3(2a+b)}{(a-1)(5a-3)} = \\ \frac{(2a+b)(5a-3)}{(a-1)(5a-3)} = \frac{2a+b}{a-1}$

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D=64-60=4
a1=(8+2)/10=1
a2=(8-2)/10=3/5

5a²-8a+3=5(a-1)(a-3/5)=(a-1)(5a-3)