2х - 2+3х-х^2+0.4х/х- 0.4=0
х^2-5.4х+2/х-0.4=0
х^2-5.4+2=0
Х-0,4≠0
Система
(3x+7y)^2=10y
(3x+7y)^2=10x
____________
10y=10x
y=x
(3x+7x)^2=10x
100x^2=10x
100x^2-10x=0| :10
10x^2-x=0
D=1-4*0*(-10)=1
x1=1-1/20=0
x2=1+1/20=1/20=1/10
х=у => y1=0
y2=1/10
<u><em>Ответ:(0;0)</em></u>
<u><em> (1/10;1/10)
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