Question

Сократите дробь x^3-2x^2-16x+32/(x-2)(x-4)

Answer 1

(x^3-2x^2-16x+32)/(x-2)(x-4)=(x^2(x-2)-16(x-2))/(x-2)(x-4)=(x^2-16)(x-2)/(x-2)(x-4)=(x-2)(x-4)(x+4)/(x-2)(x-4)=x+4

Answer 2

$\frac{x^3-2x^2-16x+32}{(x-2)(x-4)} = \frac{(x-2)(x^2-16)}{(x-2)(x-4)} =$

$\frac{(x^2-4^2)}{(x-4)} = \frac{(x-4)*(x+4)}{(x-4)} =x+4$