¬(1 ∧ (0 ∨ (1 ∧ 0))) ∧ (¬(0 ∨ 1)) = ¬(1·(0+0))·(¬1) = ¬(1·0)·0 = 0
Во 2 просто надо дописать 1 строчку
var a,b,c,m,s:integer;
begin
read(a);
b:=a mod 10;
c:=a div 10;
m:=c mod 10;
c:=c div 10;
s:=b+c+m;
write(s);
end.
3) var a:integer;
begin
read(a);
if (a mod 5=0) and (a mod 10 <>0) and (a mod 7=0) then
write('YES') else write('NO');
end.
<span>(((1v0)v1)v1)
</span>((1v1)v1)
(1v1)
1
{вот правильное решение я там забыл то чтобы подсчитывать число букв a}
<span>var </span><span><span> s</span>: string;</span><span><span>
i</span>, id, len, max, count,q: byte;</span>
begin
<span>
q:=0;
readln(s);</span><span><span>
len </span>:= length(s);</span><span><span>
max </span>:= 0;</span><span><span>
id </span>:= 0;</span>
<span><span> count </span>:= 0;</span><span>
for i:=1 to len do </span><span>
if s[i] <> ' ' then</span><span><span> count </span>:= count + 1</span><span>
else begin</span><span>
if count > max then begin</span><span><span>
max
</span>:= count;</span><span><span>
id </span>:= i - count;</span><span>
end;</span><span><span>
count </span>:= 0</span><span>
end;</span>
<span>
if count > max then begin </span><span><span>
max </span>:= count;</span><span><span>
id </span>:= i - count;</span><span>
end<span>;
</span></span>
<span> for i:=id to id+max do</span><span>
if s[i] = 'a' then begin</span><span><span> q:=q+1; s</span>[i] := 'b';</span>
<span>
writeln(s,' ' , q);</span>
end;
<span>end<span>.
</span></span>