Держи.делайте отступы,с отступами код более понятнее
<h3>1)</h3>
a = input()
b = input()
answ = ((a*a)+(b*b))
print(answ)
answ = (a**3)*(b**3)
print(answ)
<h3>2)</h3>
r = float(input("Радиус круга: "))
p = 3.14
print(r*r*p)
print(2*p*r)
<h3>3)</h3>
a, b, c = map(int, input().split())
if b >= a <= c:
print(a)
elif a >= b <= c:
print(b)
else:
print(c)
<h3>4)</h3>
<em>не забывай про табуляции</em>
def dog():
out = 0
years = int(input())
if (years <= 2):
out = years * 10.5
return out
elif (years > 2):
while(years != 2):
out += 4
years -= 1
out += 2 * 10.5
return out
def cat():
out = 0
years = int(input())
if (years <= 2):
out = years * 12.5
return out
elif (years > 2):
while(years != 2):
out += 4
years -= 1
out += 2 * 12.5
return out
if __name__ == '__main__':
pet = input()
if(pet == "собака"):
print(dog())
if(pet == "кошка"):
print(cat())
<h3>5)</h3>
со вложенными ничего не придумал
def letdothatprint():
lenght = 5
high = 7
print("* " * lenght) #Just top
while (high != 1):
print((lenght-1) * " " + "*")
high -= 1
if __name__ == '__main__':
letdothatprint()
Если да, то
0001 - 1
0010 - 2
0100 - 4
1000 - 8
10000 - 16
25 = 16 + 8 + 1 = 11001
12 = 8 + 4 = 1100
#include <iostream>
#include <cmath>
using namespace std;
void mod(int &mas, int j)
{
cin >> mas;
mas = mas / pow(2, j);
}
int main()
{
int mas[3];
int min;
for (int jjj = 0; jjj < 3; jjj++)
{
mod(mas[jjj], jjj);
if (jjj == 0)
min = 0;
else if (mas[min] > mas[jjj])
min = jjj;
};
cout << mas[min] + mas[min] * 2 + mas[min] * 4;
}