А) 2 1/3х + 1 1/15х = 6 4/5 б) (х - 3/5х) · 1 1/24 - 1 3/4 = 1 1\6
2 5/15х + 1 1/15х =6 4/5 1 1/24х - 1 1/24 · 3/5х - 1 3/4 = 1 1\6
3 6/15х = 34/5 1 1/24х - 25/24 · 3/5х - 7\4 = 7/6
51/15х = 34/5 25/24 - 5/8х - 7/4 = 7/6
х = 34/5 : 51/15 10/24х = 7/6 +7 4
х = 34/5 · 15/51 10/24х = 35/12
х = 2 х= 35/12 : 10/24
х= 35/12 · 24/10
х= 7
2) 1) 1 1/5= 2/3 х
х = 1 1/5 : 2/3
х = 6/5 · 3\2
х= 9/5м длина
2) 1 1/5 : 1 1/2 = 6\5 : 3\2 = 6/5 · 2/3 = 4/5м высота
3) V= 1 1/5 · 9/5 · 4/5 = 6/5 · 9/5 · 4/5 = 1,728 м³
4) V= (1 1/5)³= 1 1/5 · 1 1/5 · 1 1/5 = 6/5 · 6/5· 6/5 = 1,728 м³
Ответ: равно
V=s'=3t²-8t = 3*1²-8*1=3-8=-5
a=v'=6t-8=6*1-8=6-8=-2
8 1/2 : 1/4 = 17/2:1/4 = 17/2 x 4/1 = 34 пачки творога.