=(9/12-5/12)*8+1/18=1/3*8+1/18=2 2/3+1/18=2 13/18
(3x-x²-2)/(x³-5x²+4x)<0
(x-1)(2-x)/(x(x²-5x+4))<0
(x-1)(2-x)/(x((x-4)(x-1))<0 ОДЗ: x≠0 x≠1 x≠4
(2-x)/(x(4-x))<0
-∞_____+______0____-___1____-___2_____+_____4______-_____+∞
x∈(0;1)U(1;2)U(4;+∞)
F '(x)=<span>4x^3-x^2
</span>f(x)=x⁴-x³/3+C