C:N:H=(77.42/12):(15.05/14):(7.53/1)=6,5:1,1:7,53=6:1:7
C6NH7
1) n=m/M. M(Na3PO4)=164. n=348/164=2,12.
2) m=n*M. M(MnSO4)= 151. m=151*9=1359.
3) N=m*Na/M. M( P2O5)= 142. N=25*6,02*10^23/142=1,1*10^23
1.Mr(FeO)=56+16=72
2.Mr(SO3) = 32+48=80
w(O)=48/80=0.6=60%
3.m(C):m(O) = 12:16=3:4
4.Mr(H2SO4) = 1*2+32*1+16*4=98
w(H)=2/98=0.0204=2.04%
w(S)=32/98=0.3265=32.65%
w(O)=64/98=0.6531=65.31%
5.Fe:O=7/56:3/16=0.125:0.1875=1:1.5=2:3
Формула - Fe₂O₃