+17Cl)2)8)7
1s22s22p63s23p5 =)
4P + 5O2 = 2P2O5
P(0) -5e = P(+5) 4 в-ль
O(0) + 2e = O(-2) 10 ок-ль
2PH3 + 4O2 = P2O5 + 3H2O
P(-3) -8e = P(+5) 2 в-ль
O(0) +2e = O(-2) 8 ок-ль
Дано
m(CH3COOH)=120 g
m(C2H5OH)=69 g
---------------------------
m(CH3COOC2H5)-?
120 69 X
CH3COOH+C2H5OH-->CH3COOC2H5+H2O
46 88
M(CH3COOH)=60 g/mol
M(C2H5OH)=46g/mol
n(CH3COOH)=m/M=120/60=2 mol
n(C2H5OH)=m/M=69/46=1.5 mol
n(CH3COOH)>n(C2H5OH)
M(CH3COOC2H5)=88 g/mol
69 / 46 = X/88
X=132 g
ответ 132 г