Question

Решите уравнения. А) (Х+3)^2 -2 (х+3)-8=0 Б) 3^х+3^х-3=12

Answer 1

Х²+6х+9-2х-6-8=0
х²+4х-5=0
(x+5)(x-1)=0
x1=-5  x2=1


          

Answer 2

A
x+3=a
a²-2a-8=0
a1+a2=2 U a1*a2=-8
a1=-2⇒x+3=-2⇒x=-5
a2=4⇒x+3=4⇒x=1
Б
3^(x-3)*(27+1)=12
3^(x-3)*28=12
3^(x-3)=3/7
x-3=log(3)(3/7)
x=3+1-log(3)7
x=4-log(3)7