№1. а) CH3-CH2-CH3
CH2=CH2
№2. свет
1)C3H8+Cl2=C3H7Cl+HCl
2)CH3-CH2-CH2-Cl+ NAOH=CH3-CH2-CH2-OH+NACl
O2+2H2 = 2H2O
O3 + 3H2 = 3H2O
m(O3) = 8*10/100 = 0.8г
m(O2) = 8-0.8 = 7.2г
n(O3) = m/M = 0.8/48 = 0.017моль
n(O2) = m*M = 7.2/32 = 0.225моль
n(H2) = 2*n(O2) = 2*0.225 = 0.45моль
n(H2) = 3*n(O3) = 3*0.017 = 0.051моль
<span>m(H2) = M*n = 2*(0.45+0.051) = 1.002г
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N2+6Na=2Na3N
N(0)+3e=N(-3) 1 2
Na(0)-1e=Na(+1) 3 6
N2+3H2=2NH3
N2(0)+6e=2N(-3) 1
H2(0)-2e=2H(+) 3
CH2=CH-CH3 +Cl2 = CH2=CH-CH2Cl+HCl
CH2=CH-CH2Cl+H2 = CH3-CH2-CH2Cl
CH3-CH2-CH2Cl+KOH = CH3-CH2-CH2OH+KCl
CH3-CH2-CH2OH (t,H2SO4) = CH3-CH=CH2+H2O
CH3-CH=CH2+HOH= CH3-CH(OH)-CH3.
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<span>дано:<span>
m(N</span>₂) = 380 г<span>
найти: n(N</span>₂), V(N₂),<span>
решение:
M(N</span>₂) = 14*2
= 28г\моль<span>
n(N</span>₂) = m\M =
380 г\28 г\моль = 13,6моль<span>
V(N</span>₂) = Vm *n
= 22,4 л\моль*13,6 моль = 304 л<span>
ответ:n(N</span>₂) = 13,6 моль, V(N₂<span>)<span> = 304 л</span></span></span>