M(CxHyClz)=5,25*32=168; n(C)=14,28:12=1,19; n(H)=1,2; n(Cl)=84,52:35,5=2,4;
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POH = -lg 0.0001 = 4, след-но pH = 14-pOH = 10 (среда ЩЕЛОЧНАЯ).
<em><span> </span>2CH3COOH + CaO = (CH3COO)2Ca + H2O </em><em>Наблюдаем растворение оксида кальция</em>