1/(√2-1)=1/(√2-1) . (√2+1)/(√2+1)=1.(√2+1)/((√2-1)(√2+1))=
=(√2+1)/(2-1)=√2+1
(√7+√3)(√7-√3)=7-3=4
3√12.4√8=3.4.√(12.8)=12√96=12√(4.24)=12√(4.4.6)=
=12√(16.6)=12.4.√6=48√6
20√18:5√2)=20√(9.2):5√2=20.3.√2:5√2=12
5√6(√6-√3)=5√6.√6-5√6.√3=5.6-√(6.3)=
=30-√18=30-√(9.2)=30-3√2
3√5.(1+2√5)=3√5+6.5=3√5+30
(5√2)ˇ25:(5√2)ˇ23=(5√2)ˇ(25-23)=(5√2)²=5².(√2)²=25.2=50
Ответ:
Нельзя
Объяснение:
Нельзя без остатка, так как у 25 и 28 нет общих делителей.
Удачи!
√(97-56√3) = 7-4√3
97-56√3=(7-4√3)²
97-56√3=49-56√3+16*3
97-56√3=97-56√3 (РАВЕНСТВО верно)
Решение. Способ 1<span><span>f′</span>(x)=<span><span>(<span><span>4⋅x−7 / </span><span>x2</span></span>)</span>′</span>=
</span><span>=(<span><span><span><span>(4⋅x−7)</span>′</span>⋅<span>x2</span>−<span>(4⋅x−7)</span>⋅<span><span>(<span>x2</span>))</span>′ / </span></span><span><span>(<span>x2</span>)</span>2</span></span>=
</span><span>=<span><span><span><span>(4⋅x)</span>′</span>⋅<span>x2</span>−<span>(4⋅x−7)</span>⋅2⋅x</span><span><span>(<span>x2</span>)</span>2</span></span>=
</span><span>=<span><span>4⋅<span>x2</span>−<span>(4⋅x−7)</span>⋅2⋅x / </span><span><span>(<span>x2</span>)</span>2
</span></span></span>Ответ:<span>f′</span>(x)=<span><span>4⋅<span>x2</span>−<span>(4⋅x−7)</span>⋅2⋅x / </span><span><span>(<span>x2</span>)</span><span>2</span></span></span>