Question

Вычислите раскрывая скобк:
1. 3(x+3)-3(4-x)-x-3=?
2. 3(х+5)-(4-х)-(1+3)х-3=?
3.2(х+4)-3(2-х)-х-4=?
4.х+1-5(2-х)-(5+1)х-5=?
5.х+3-(2-х)-х-4=?
6.4(х+3)-(5-х)-х-4=?
7. 3(х +3)-4(1-х)-(4+3)х-1=?
8.5(х+5)-3(3-х)-х-3=?

Answer 1

1. 3(x+3)-3(4-x)-x-3= 3х + 9 - 12 + 3х - х - 3 = 5х - 6;
2. 3(х+5)-(4-х)-(1+3)х-3= 3х + 15 - 4 + х - х - 3х - 3 = 8;
3.2(х+4)-3(2-х)-х-4= 2х + 8 - 6 + 3х - х - 4 = 4х - 2;
4.х+1-5(2-х)-(5+1)х-5= х + 1 - 10 + 5х - 5х - х - 5 = - 14;
5.х+3-(2-х)-х-4= х + 3 - 2 + х - х - 4 = х - 3;
6.4(х+3)-(5-х)-х-4= = 4х + 12 - 5 + х - х - 4 = 4х + 3;
7. 3(х +3)-4(1-х)-(4+3)х-1= = 3х + 9 - 4 + 4х - 7х - 1 = 4;
8.5(х+5)-3(3-х)-х-3= 5х + 25 - 9 + 3х - х - 3 = 7х + 13;