Log2 (x^2+8)-log2 (x-1)<span>=log0,5 1/8
ОДЗ:
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x∈(-1;+∞)
log2((x^2+8)/(x-1))=-log2(1/8)
((x^2+8)/(x-1))-8=0
(x^2+8-8x+8)/(x-1)=0
(x^2-8x+16)/(x-1)=0
(x-4)^2/(x-1)=0
x=4(x∈ОДЗ)
Ответ: х=4
ОДЗ:
</span>
x∈(-1;+∞)
log2((x^2+8)/(x-1))=-log2(1/8)
((x^2+8)/(x-1))-8=0
(x^2+8-8x+8)/(x-1)=0
(x^2-8x+16)/(x-1)=0
(x-4)^2/(x-1)=0
x=4(x∈ОДЗ)
Ответ: х=4