1)1/8=0.125
2)(2(k+1)+3(n+1))/((n+1)*(k+1))=(2k+2+3n+3)/((n+1)*(k+1))=(2k+3n+5)/((n+1)*(k+1))
А)3/4 = 0.75
Б)1/8= 0.125
В)3/50=0.06
Г)1/25 = 0.04
А) 6ab-3b² = 3b(2a-b)
Б) ac+bc-3a-3b = c(a+b)-3(a+b) = (c-3)(a+b)