Question

Найти нули функции y=2x^2+6x+4 y=6x^2+4x

Answer 1

$1. \\ y=2x^2+6x+4 \\ 2x^2+6x+4=0 \\ x^2+3x+2=0 \\ D=3^2-4*2=9-8=1 \\ x= (-3б \sqrt{1)} :2 \\ x_{1} =-2;x_2=-1\\ \\ 2. \\ y=6x^2+4x \\ 6x^2+4x=0 \\ 3x^2+2x=0 \\ x(3x+2)=0 \\ x_1=0; \\ 3x_2+2=0 \\ 3x_2=-2 \\ x_2=-2/3$