M₁=100*5%/100%=5г
m₂=300*20%/100%=60г
m(сахара)=5+60=65г
m(раствора)=300+100=400г
ω=m(сахара)/m(раствора)*100%=65*100%/400г=16,25%
x 4,5
C3H8+ 5O2=3CO2+4H2O
1 3
n(CO2)=4,5 moll
n(C3H8)=x=4,5*1/3=1,5 moll
V(C3H8)=Vm*n=22,4*1,5=33,6 dm3 - otvet
zadacha reshena)))
CaO + 3C = CaC2 + CO
CaC2 + 2HOH = Ca(OH)2 + C2H2
C2H2 + HOH (HgSO4) = CH3COH
CH3COH + Ag2O = CH3COOH + 2Ag
2CH3COOH + Ca = (CH3COO)2Ca + H2