1) 1101 0101(2) = 213(10)
324(8) = 212(10)
C5(16) = 197(10)
В порядке возрастания C5(16), 324(8), 11010101(2)
1.2) 245(10) = 1111 0101(2) = 365(8) = F5(16)
2) 10101110(2) – 256(8) + A(16) = 10(10)
32 = 2^5 i=5
Ответ: 5
16 = 2^4 i=4
I=i*K=4*50=200
Ответ: 200
#include <iostream>
using namespace std;
int main()
{
int n = 0, f = 0, t = 0;
cin >> n;
if (n <= 1015 && n >= 1) {
for (int i = 1; i <= n; ++i) {
t = -i;
if (i % 2 == 0) {
t = abs(t);
}
cout << t << " ";
f += t;
}
} else {
cout << "Error" << endl;
}
cout << endl << "Res: " << f;
return 0;
}
===== PascalABC.NET =====
begin
var Y := ReadInteger('Y =');
if Y in Range(10, 99) then
Println(Y + 18)
end.