Using System;
public class Test
{
public static void Main()
{
double a, b, x, p=1;
int k=0;
Console.Write("a = ");
a = double.Parse(Console.ReadLine());
Console.Write("b = ");
b = double.Parse(Console.ReadLine());
for (int i=1; i <= 8; i++) {
x = double.Parse(Console.ReadLine());
if ((x>=a)&&(x<=b)){
k++; p*=x;
}
}
Console.WriteLine("k = {0} p = {1}", k,p);
Console.ReadKey();
}
}
Пример:
a = 3
b = 8
7
9
2
0
6
4
3
5
k = 5 p = 2520
Условие:
((x >=-1)&&(y<=1)&&(y>=x))
Const n=10;
var A : Array [1..10] of integer;
i, mini, maxi, min,max, c,k: integer;
begin
for i := 1 to n do
begin
A[i] := random(10);
write(' ',A[i]);
end;
maxi:=1;
mini:=1;
For i:=1 to n do
begin
min:=A[1];
If A[i]>max then
begin
max:=A[i];
maxi:=i;
end;
If A[i]<min then
begin
min:=A[i];
mini:=i;
end;
c:=A[maxi];
A[maxi]:=A[mini];
A[mini]:=c;
end;
Writeln;
for i:=1 to n do
begin
Write(' ',a[i]);
end;
Writeln;
for i:=1 to n do
begin
If a[i]>4 then
begin
a[i]:=4;
inc(k);
end;
Write(' ',a[i]);
end;
Writeln;
Write('Количество: ',k);
<span>end.</span>
program
zadagha_1;
var
a:
array[1..8] of integer;
i,sum:integer;
begin
writeln('vvedite
8 chisel');
for i:=1 to
8 do read(a[i]);
sum:=0;
for i:=1 to
8 do begin
if i mod 2
<> 0 then begin
sum:=sum+a[i];
writeln(a[i]);
end;
end;
writeln();
writeln('summa
elementov c nechetnim N =', sum);
end.
program
zadagha_2;
var
b:
array[1..1000] of integer;
i,a,n:integer;
begin
writeln('vvedite
chislo - kolichestvo elementov massiva');
readln(n);
for i:=1 to
n do begin
b[i]:=random(1000);
write(b[i]:6);
end;
writeln();
writeln('vvedite
chislo');
readln(a);
write
('elementi > dannogo chisla: ');
for i:=1 to
n do begin
if
b[i]>a then write (i:4);
end;
end.
program
zadacha_3;
var
a:
array[1..100] of integer;
i,n,k:
integer;
begin
n:=random(100);
for i:=1 to
n do begin
a[i]:=random(1000)-500;
write(a[i]:6);
end;
writeln();
writeln('vvedite
chislo');
readln(k);
writeln('v
massive chisly ',k, ' kratni: ');
for i:=1 to
n do begin
if (a[i] mod k = 0) and (a[i]>0) then begin
write(a[i]:6);
end;
end;
end.
Существует 16*8 = 128 вариантов местонахождения книги. Из этих количеств вариантов необходимо выбрать один.
N = 128, а I = 7, т.к. 128 = 2^7
Ответ: 7 бит