Ответ:0.1011*10*(-100)=101,1
Объяснение:
1)0,1011*10=1,011
2)1,011*(-100)=101,1
* это умножение
24+8=32
log2(32)=5
39x5=195 бит = 24 байта
<span>var a, b: integer;
begin<span>
writeln(<span>'Введите часы: '</span>);</span>
readln(a);<span>
writeln(<span>'Введите минуты: '</span>);</span>
readln(b);<span>
if (a > 6) and (a < 10) then writeln(<span>'Утро'</span>);
</span><span> if (a = 10) and (b = 0) then writeln(<span>'Утро'</span>);
</span><span> if (a = 6) and (b >= 30) then writeln(<span>'Утро'</span>);</span><span>
if (a > 10) and (a < 16) then writeln(<span>'День'</span>);</span><span>
if (a = 10) and (b >= 1) then writeln(<span>'День'</span>);</span><span>
if (a = 16) and (b <= 30) then writeln(<span>'День'</span>);</span><span>
if (a > 16) and (a < 22) then writeln(<span>'Вечер'</span>);</span><span>
if (a = 22) and (b = 0) then writeln(<span>'Вечер'</span>);</span><span>
if (a = 16) and (b >= 31) then writeln(<span>'Вечер'</span>);</span><span>
if (a > 22) or (a < 6) then writeln(<span>'Ночь'</span>);
</span><span> if (a = 22) and (b >= 1) then writeln(<span>'Ночь'</span>);
</span><span> if (a = 6) and (b <= 30) then writeln(<span>'Ночь'</span>);
</span><span>end.</span></span>
14400. один бит равен одному символу.
Ответ:
import random as r
s=[r.randint(1,100) for i in range(10)]
print(s)
m1=max(s)
s.remove(m1)
m2=max(s)
print(m1,m2)
Объяснение:
