<span>1) cosA=4/2/8=2/8=0,25</span>
..................................................НА 20 км.ч................................)
1) 3:4=0,75 (кг)
2) 2:5=0,4 (м)
3) 3:6=0,5 части яблока, то есть половина яблока
sin150<span>°</span>+sin75<span>°</span>=sin(180<span>°</span>-150<span>°</span>)+sin(30<span>°</span>+45<span>°</span>)= -sin30<span>°</span>+sin30<span>°*cos45<span>°+sin45<span>°*cos30<span>°= -1/2+ 1/2* <span>√2/2+ <span>√2/2*<span>√3/2= -1/2+<span>√2/4+<span>√6/4=(<span>√2+<span>√6-2)/4=<span>√2(1+<span>√3-<span>√2)/4</span></span></span></span></span></span></span></span></span></span></span></span></span></span>
<span><span><span><span><span><span><span><span><span><span><span><span><span><span>Ну как-то так</span></span></span></span></span></span></span></span></span></span></span></span></span></span>